The Ksp of calcium carbonate, CaCO3, is 3.36 10-9. We need to take into account the hydrolysis of the carbonate ion with K2 = 4.8x10-11: HCO3- H + CO3. The solubility of calcite in water is 0.67 mg/100 mL. Calcium hydroxide Ca(OH) 2 5.5×10 –6. The Ksp of calcium carbonate is 5.0x10-9: 2+ 2CaCO3(s) Ca + CO3. Comparison of solubility of calcium carbonate with different salts of calcium has shown in table 1, and it can be conclude that only calcium carbonate has an extremely low solubility. Answer 4.5 × 10 −9. What is the concentration of Ca2+ ions in? Calcium sulfite CaSO 3 6.8×10 –8. Calcium chromate CaCrO 4 7.1×10 –4. Calcium hydrogen phosphate CaHPO 4 1×10 –7. Calcium fluoride CaF 2 5.3×10 –9. Write an expression for Ksp for the dissolution of PbCl2. Answer Save. The Ksp Of Calcium Carbonate, CaCO3, Is 3.36; Question: The Ksp Of Calcium Carbonate, CaCO3, Is 3.36. Umar. At 25°C and pH 7.00, Ksp for calcium phosphate is 2.07 × 10 −33, ... One crystalline form of calcium carbonate (CaCO 3) is the mineral sold as “calcite” in mineral and gem shops. See the answer. … Calculate its K sp. Relevance. 5 years ago. Lv 7. Write an expression for Ksp for the dissolution of CaCO3. Ksp = [Ca^2+][CO3^2-] = 0.292 X 10^-3 X 0.195 x 10^-3 = 5.694 x 10^-8 . Write an expression for Ksp for the dissolution of AgI. Expert Answer 100% (7 ratings) Previous question Next question Transcribed Image Text from this Question. Calcium sulfate CaSO 4 9.1×10 –6. a. Favorite Answer. Calcium phosphate Ca 3 (PO 4) 2 2.0×10 –29. Ksp = [Ca2+] [CO32-] (1) If you don't take into account the hydrolysis of the carbonate ion the solubility S is S = [Ca2+] = [CO32-] = Ksp neglecting hydrolysis of CO32(2) The estimated solubility would be 7.1x10-5M. a. Calcium oxalate CaC 2 O 4 2.7×10 –9. If you have a compound that is 1:1 between the cation and anion it has a formula like AB. For CuCO3, the respective ions are +2 and -2. 3.) Expert Answer 100% (56 ratings) Previous question Next question Get more help from Chegg. Calcium carbonate, CaCO3 has a solubility product Ksp = 8.7 x 10-9. Write a balanced equation for the dissolution of PbCl2 b. b. CaCO3 = Ca^2+ + CO3^2-Ksp = [Ca^2+][CO3^2-] Now [Ca^2+] = [CO3^2-] = 11.77ppm = 11.7mg/L [Ca^2+] = 11.7/40.08 = 0.292mM, and [CO3^2-] = 11.7/60 = 0.195mM. Ksp of AB is written: AB(s) <=> A^+n(aq) + B^-n(aq) Ksp = [A^+n][B^-n] So, if A is +2 and B is -2 then you just replace the +n and -n with the appropriate number. Best Answer 80% (5 ratings) Previous question Next question Get more help from Chegg. The Ksp expression is fairly easy to write when you figure out the procedure. This problem has been solved! 2.) Review for Ch. Calculate the solubility of this compound in g/L. Using this concentration and the measured pH = 8.61, calculate KSP of CaCO3. Show transcribed image text. Calcium carbonate CaCO 3 2.8×10 –9. The Ksp of calcium carbonate, CaCO3, is 3.36 . Write a balanced equation for the dissolution of AgI. 1 Answer.

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